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n=int(input())

m=int(input())

s=input()

t=input()

def subString(s,n):

    c=0

    for i in range(n):

        for len in range(i+1,n+1):

             a=s[i: len]

             c+=1

    return c-2

if s==t:

    print(1)

else:

    if t in s:

        print(subString(s,n))

    else:

        print(0)

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Angry professor 

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#include <math.h>

#include <stdio.h>

#include <string.h>

#include <stdlib.h>

#include <assert.h>

#include <limits.h>

#include <stdbool.h>

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int main(){

    int t,count=0; 

    scanf("%d",&t);

    for(int a0 = 0; a0 < t; a0++){

        count=0; 

        int n; 

        int k; 

        scanf("%d %d",&n,&k);

        int a[n];

        for(int a_i = 0; a_i < n; a_i++){

           scanf("%d",&a[a_i]);

        }

        

        for(int a_i = 0; a_i < n; a_i++){

           if(a[a_i]<=0)

               count++;

        }

        if(count<k)

            printf("YES\n");

        else

            printf("NO\n");

        //count=0;

    }

    return 0;

}

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C language

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n = int(input())

a = list(map(int,input().split()))

c = 0

for i in range(n-1):

  for j in range(i+1:n):

    s1 = sum(list(map(int,bin(i)[2:].split())))

    s2 = sum(list(map(int,bin(j)[2:].split())))

    if s1 == s2:

      c += 1

print(c)

Python

Bob and Numbers Code

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n=int(input())

x=int(input())

y=int(input())

z=int(input())

a=[]

for i in range(n):

    a.append(int(input()))

s=(x*1)+(y*2)+(z*3)

c=0

for i in a:

    if i<=s:

        c+=1

print(c)

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John has an array

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class Main {

 public static void main(String[] args) {

   int[] numbers = {2, -9, 0, 5, 12, -25, 22, 9, 8, 12};

   int sum = 0;

   Double average;

   

   // access all elements using for each loop

   // add each element in sum

   for (int number: numbers) {

     sum += number;

   }

  

   // get the total number of elements

   int arrayLength = numbers.length;

   // calculate the average

   // convert the average from int to double

   average =  ((double)sum / (double)arrayLength);

   System.out.println("Sum = " + sum);

   System.out.println("Average = " + average);

 }

}

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/># Python3 program to find the lexicographically

# smallest string by removing at most one character

# Function to return the smallest string

def smallest(s):

 l = len(s)

 ans = ""

 # iterate the string

 for i in range (l-1):

  # first point where s[i]>s[i+1]

  if (s[i] > s[i + 1]):

   # append the string without

   # i-th character in it

   for j in range (l):

    if (i != j):

     ans += s[j]

   

   return ans

 # leave the last character

 ans = s[0: l - 1]

 return ans

# Driver Code

if name == "main":

 s = "abcda"

 print (smallest(s))

# This code is contributed by ita_c

✅lexpgraphic code

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int res=X*1  + Y*2 + Z*3;

int count=0;

for(int i=0;i<A.size();i++){

if(A.get(i)<=res){

count++;

}

}

return count; 

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N= int ( input())

L= list( map(int,input.split()))

K=int (input())

If k in L:

    print (L.index(k)+1)

else:

    print(-1)

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